v^2-vd-20d^2=

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Solution for v^2-vd-20d^2= equation: 


Simplifying
v2 + -1vd + -20d2 = 0

Reorder the terms:
-1dv + -20d2 + v2 = 0

Solving
-1dv + -20d2 + v2 = 0

Solving for variable 'd'.

Factor a trinomial.
(-4d + -1v)(5d + -1v) = 0


Subproblem 1
Set the factor '(-4d + -1v)' equal to zero and attempt to solve:

Simplifying
-4d + -1v = 0

Solving
-4d + -1v = 0

Move all terms containing d to the left, all other terms to the right.

Add 'v' to each side of the equation.
-4d + -1v + v = 0 + v

Combine like terms: -1v + v = 0
-4d + 0 = 0 + v
-4d = 0 + v
Remove the zero:
-4d = v

Divide each side by '-4'.
d = -0.25v

Simplifying
d = -0.25v

Subproblem 2
Set the factor '(5d + -1v)' equal to zero and attempt to solve:

Simplifying
5d + -1v = 0

Solving
5d + -1v = 0

Move all terms containing d to the left, all other terms to the right.

Add 'v' to each side of the equation.
5d + -1v + v = 0 + v

Combine like terms: -1v + v = 0
5d + 0 = 0 + v
5d = 0 + v
Remove the zero:
5d = v

Divide each side by '5'.
d = 0.2v

Simplifying
d = 0.2v
Solution
d = {-0.25v, 0.2v}

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